Science

An automobile engine slows down from 4500rpm…

Question: “an automobile engine slows down from 4500rpm to 1200rpm in2.5seconds..Calculate..A) Angular Acceleration assumed constant, andB) The total number of revolutions the engine makes in this time” Answer: α=(ω2-ωo2)/t, so first convert the rpm’s torad/s then you get 472.5rad/s and 126rad/s andthe acceleration is -138.6rad/s2. The total revolutions that are made areΔθ=1/2Δωt=748rads, so748rads/2Ï€=1.2x102revolutions Click to …

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