What mass of ice at -10.2°C is needed to cool…

Question:

What mass of ice at -10.2°C is needed to cool a whale’s water tank, holding 1.09 103 m3 of water, from 20.0°C down to a more comfortable 10.0°C?

Answer:

1.09 X 103 m3 = 1.09 x 106 kg of water.

specific heat of water C = 4.187 kJ / kg

latent heat of fusion = 334 kJ/kg

so lets suppose m mass of ice is needed ,

m X 4.187 X (0 -(-10.2)) + m X 334 + m X 4.187 X (10 – 0) = 1.09 x 106 X 4.187 X (20-10)

m ( 42.707 + 334 + 41.87 ) = 45.638 X 106

m = 1.09 X 105 kg ice needed

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