An automobile engine slows down from 4500rpm…


“an automobile engine slows down from 4500rpm to 1200rpm in2.5seconds..Calculate..
A) Angular Acceleration assumed constant, and
B) The total number of revolutions the engine makes in this time”


α=(ω2-ωo2)/t, so first convert the rpm’s to
rad/s then you get 472.5rad/s and 126rad/s and
the acceleration is -138.6rad/s2. The total revolutions that are made are
Δθ=1/2Δωt=748rads, so748rads/2π=1.2x102revolutions

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