**Question:**

A gas sample is heated from -20.0°C to 57.0°C and the volume is increased from 2.00 L to 4.50 L. If the initial pressure is 0.109 atm, what is the final pressure?

A. 0.0371 atm

B. 0.188 atm

C. 0.320 atm

D. 0.0632 atm

E. –0.138 atm

**Answer:**

we have a relation

P1V1/T1 = P2V2/T2

P1 = 0.109 atm , V1 = 2.00 L , T1 = -20.00C = 253 K

P2 = ? , V2 = 4.50 L , T2 = 570C = 330 K

P2 = (P1V1T2 /T1V2)

P2 = (0.109 x 2.00 x 330 / 253 x 4.50)

P2 = 71.94 /1138.5

P2 = 0.0632 atm

answer = option D = 0.0632 atm